Question

求f(x)=2sin(2x+π/6)在区间[0,π]的单调递增区间,

Answer 1

f(x)=2sin(2x+π/6)
设t=2x+π/6,t∈[π/6,2π+π/6]
f(t)=2sint
f(t)的单调递增区间为：
t∈[π/6,π/2]或t∈[3π/2,2π+π/6]
此时：
x∈[0,π/6]或x∈[2π/3,π].
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