Question

解方程（x-1）（x-2）分之3x-4=x-1分之A+x-2分之B,求A,B的值

Answer 1

右边：A/(x-1)+B/(x-2)
=[A(x-2)+B(x-1)]/(x-1)(x-2);
=[(A+B)x-2A-B]/(x-1)(x-2);
所以A+B=3;
-2A-B=-4;
A=1;
B=2;