Question

y=x的平方分之1乘以e的2x次幂,求dy

Answer 1

y=e^(2x)/x^2

dy
=(1/x^2)d(e^(2x)) + e^(2x) d(1/x^2)
=(1/x^2)e^(2x)d(2x) + e^(2x)[(-2/x^3) dx]
=(1/x^2)e^(2x)(2dx) + e^(2x)[(-2/x^3) dx]
=(2/x^2)e^(2x) ( 1 - 1/x) dx