Question

MCS-51单片机的编程题：已知系统晶振频率为12MHZ，采用定时器T0的方式1，请编程实现1s的延时。

Answer 1

DELAY1S:
    MOV TMOD,#01H
    MOV TH0,#HIGH(65536-50000)
    MOV TL0,#LOW(65536-50000)
    SETB TR0
    MOV R2,#20
LOOP:
    JNB TF0,$
    CLR TF0
    CLR TR0
    MOV TH0,#HIGH(65536-50000)
    MOV TL0,#LOW(65536-50000)    
    SETB TR0
    DJNZ R2,LOOP
    RET

Answer 2

void delay(uint x)
{
uchar j;
uint i;
for(i=0;i<x;i++)
for(j=0;j<100;j++);
}

Answer 3

#include <reg51.h>

void InitTimer0(void)
{
TMOD = 0x04;
TH0 = 0x1C;
TL0 = 0x18;
EA = 1;
ET0 = 1;
TR0 = 1;
}

Answer 4

void timer0() interrupt 1
{
uchar count;
TH0 = (65536-50000)/256;
TL0 = (65536-50000)%256;
count++;
if(count == 20)
{
count = 0;
sec++;
if(sec == 100)
{
sec = 0;
}
}
}

Answer 5

1楼说了，主程序里还要定义一下的。1秒用定时器来实现，还有很多种方法的