
2个回答
展开全部
解法一:原式=1/2+1/4+1/8+1/16+1/32+(1/64+1/64)-1/64
=1/2+1/4+1/8+1/16+(1/32+1/32)-1/64
=1/2+1/4+1/8+(1/16+1/16)-1/64
=............
=(1/2+1/2)-1/64
=1-1/64
=63/64
解法二: 设原式=S,两边同时乘以64,则
64S=32+16+8+4+2+1=63
因此 S=63/64
解法三:原式=1/64(32+16+8+4+2+1)
=1/64*63
=63/64
=1/2+1/4+1/8+1/16+(1/32+1/32)-1/64
=1/2+1/4+1/8+(1/16+1/16)-1/64
=............
=(1/2+1/2)-1/64
=1-1/64
=63/64
解法二: 设原式=S,两边同时乘以64,则
64S=32+16+8+4+2+1=63
因此 S=63/64
解法三:原式=1/64(32+16+8+4+2+1)
=1/64*63
=63/64
展开全部
解法一:原式=1/2+1/4+1/8+1/16+1/32+(1/64+1/64)-1/64
=1/2+1/4+1/8+1/16+(1/32+1/32)-1/64
=1/2+1/4+1/8+(1/16+1/16)-1/64
=(1/2+1/2)-1/64
=1-1/64
=63/64
解法二:设原式=S,两边同时乘以64,则
64S=32+16+8+4+2+1=63
S=63/64
解法三:原式=1/64(32+16+8+4+2+1)
=1/64*63
=63/64
解法四:1/2+1/4+1/8+1/16+1/32+1/64
=32/64+16/64+8/64+4/64+2/64+1/64
=63/64
=1/2+1/4+1/8+1/16+(1/32+1/32)-1/64
=1/2+1/4+1/8+(1/16+1/16)-1/64
=(1/2+1/2)-1/64
=1-1/64
=63/64
解法二:设原式=S,两边同时乘以64,则
64S=32+16+8+4+2+1=63
S=63/64
解法三:原式=1/64(32+16+8+4+2+1)
=1/64*63
=63/64
解法四:1/2+1/4+1/8+1/16+1/32+1/64
=32/64+16/64+8/64+4/64+2/64+1/64
=63/64
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询