Question

求下列函数的定义域:(1)y=lg(2sinx-1)+根号(1-2cosx);(2)y=根号(sinx-cosx)

Answer 1

1.﹛2sinx-1＞0
﹛1-2cosx≥0
解得2kπ+π/3≤x＜5π/6+2kπ,k∈Z
即函数定义域为2kπ+π/3≤x＜5π/6+2kπ,k∈Z
2.sinx-cosx≥0
解得2kπ+π/4≤x≤5π/4+2kπ,k∈Z
即函数定义域为2kπ+π/4≤x≤5π/4+2kπ,k∈Z