Question

解不等式组：{[5(x-1)/6]-1>[2(x+1)/3];2+[3(x+1)/8]<3-[x-1/4]}

要全部过程、、快点啊！！
谢谢了！！

Answer 1

5(x-1)/6-1>2(x+1)/3(1)
2+3(x+1)/8<3-(x-1/4)(2)

5(x-1)/6-1>2(x+1)/3(1)
5x-5-6>4x+4
x>15
2+3(x+1)/8<3-(x-1/4)(2)
16+3x+3<24-8x+2
11x<7
x<7/11

方程组x属于空集