Question

C++编程 已知A>B>C,A+B+C<100,求满足1/A*A+1/B*B=1/C*C的共有多少组

Answer 1

A,B,C应该是正整数吧？
int count=0;
for(int a=0;a<100;a++)
{
for(int b=0;b<a;b++)
{
if(a+b>=100)break;
for(int c=0;c<b;c++)
{
if(a+b+c>100)break;
if(1/A*A+1/B*B=1/C*C)count ++;
//这里要转换成double类型，这里不能用=号，要有个误差范围
}
}
}
cout<<count;

Answer 2

#include <iostream>
using namespace std;
int main()
{
int A,B,C;
int num = 0;
for( C = 1; C != 33; ++ C )
for( B = 100; B != C; -- B )
for( A = 100; A != B; -- A)
{
if( (A + B + C < 100) && ( (A * A * B * B) == ((A * A + B * B) * C * C) ) )
{
cout << A << "\t" << B << "\t" << C << endl;
++ num;
}
}
cout << "num is:" << num << endl;
}