Question

求教小学简便运算题1.（12.34+23.41+34.12+41.23)/(1+2+3+4）2.41.2X8.1+537

Answer 1

1、原式=[(12+23+34+41)+(0.12+0.23+0.34+0.41)]/10 =[101*(0.12+0.23+0.34+0.41)]/10 =(101*1.1)/10=11.112、原式=412*0.81+537*0.19 =412*0.81+412*0.19+125*0.19 =412*1+23.75 =435.753、原式=[(5*1.7)*(7*1.9)*(4*1.8)]/(1.7*1.8*1.9) =5*7*4=1404、原式=99+99*99*100 =99+980100=9801995、原式=2009+2009*0.0001+0.9999*2009 =2009+2009+2009*0.0001-0.0001*2009 =2009+2009=40186、题目真的有问题.是9个5不是8个.因为111111111/12345679=9 所以a=666666666/12345679=6*（111111111/12345679）=54 b=555555555/12345679=5*（111111111/12345679）=45 a+b=54+45=99这可是有过程的哈,