根号下x平方加y平方加z平方分之xyz的偏导数怎么求
1个回答
展开全部
u = xyz/√(x²+y²+z²).....................................................(1)
∂u/∂x = [yz√(x²+y²+z²)-xxyz/√(x²+y²+z²)]/(x²+y²+z²)
= yz(y²+z²)/(x²+y²+z²)√(x²+y²+z²).......................(2)
∂u/∂y = xz(x²+z²)/(x²+y²+z²)√(x²+y²+z²).......................(3)
∂u/∂z = xy(y²+x²)/(x²+y²+z²)√(x²+y²+z²).......................(4)
∂u/∂x = [yz√(x²+y²+z²)-xxyz/√(x²+y²+z²)]/(x²+y²+z²)
= yz(y²+z²)/(x²+y²+z²)√(x²+y²+z²).......................(2)
∂u/∂y = xz(x²+z²)/(x²+y²+z²)√(x²+y²+z²).......................(3)
∂u/∂z = xy(y²+x²)/(x²+y²+z²)√(x²+y²+z²).......................(4)
本回答被网友采纳
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
