Question

三角函数公式的问题sin^A+sin^B=sin(A+B)sin(A-B)是怎么解得,sin^2A—sin^2B 是A？

Answer 1

sin(A+B)sin(A-B)
=-1/2*[cos(A+B+A-B)-cos(A+B-A+B)]
=-1/2[cos2A-cos2B]
=-1/2[1-2sin^2A-(1-2sin^2B)
=-1/2[-2sin^2A+2sin^2B]
=sin^2A-sin^2B,2,让我想想,2,sin^A什么意思？,1,到底是哪个,1,把后面用积化和差公式变形再做,1,sin(A+B) = sinAcosB + cosAsinB
sin(A-B) = sinAcosB - cosAsinB
sin(A+B)sin(A-B)
= (sinAcosB + cosAsinB)(sinAcosB - cosAsinB)
= sin^2 Acos^2 B - cos^2 Asin^2 B
- -...不相等啊,1,得不到啊，也许是我错了。从右向左推，结果：(sinA+sinB)(sinA-sinB),0,三角函数公式的问题
sin^A+sin^B=sin(A+B)sin(A-B)是怎么解得,
sin^2A—sin^2B 是A B的平方，对不起打错了 就是这个，平方，