Question

求导，这怎么来的

Answer 1

链式法则：dz/dx=dz/dy*dy/dx 即z对x求导 = z对y求导 * y对x求导代入即得(lny)' = 1/y * y'

Answer 2

∫(0->1) x(α+1)x^α dx
=(α+1) ∫(0->1) x^(α+1) dx
=[(α+1)/(α+2)] [ x^(α+2) ]|(0->1)
=(α+1)/(α+2)