求大神速解
1个回答
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2y''-3y-3x=1
2y''-3y =3x+1
let
yp = Ax +B
yp'=A
yp''=0
2y''-3y =3x+1
-3(Ax+B) = 3x+1
=>
A=-1 , B= -1/3
The aux. equation
2p^2-3 =0
p = √6/2 or - √6/2
let
yg = Ce^[(√6/2)x] + De^[-(√6/2)x]
y=yg+yp =Ce^[(√6/2)x] + De^[-(√6/2)x] -x -1/3
2y''-3y =3x+1
let
yp = Ax +B
yp'=A
yp''=0
2y''-3y =3x+1
-3(Ax+B) = 3x+1
=>
A=-1 , B= -1/3
The aux. equation
2p^2-3 =0
p = √6/2 or - √6/2
let
yg = Ce^[(√6/2)x] + De^[-(√6/2)x]
y=yg+yp =Ce^[(√6/2)x] + De^[-(√6/2)x] -x -1/3
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