Question

几道C语言程序题求解

1.编程计算1至500中是7的倍数的数值之和。
2.编程求1至100之间奇数之和及偶数之和。

Answer 1

1)
#include "stdio.h"
int main()
{ int i,s=0;
for(i=7;i<500;i+=7)
s+=i;
printf("%d\n",i);
return 0;
}
2)
#include "stdio.h"
int main()
{ int i,s1=0,s2=0;
for(i=1;i<101;i++)
i%2?s1+=i:s2+=i;
printf("100以内奇数之和=%d\n",s1);
printf("100以内偶数之和=%d\n",s2);
return 0;
}

Answer 2

#include<stdio.h>

#include<stdlib.h>

int main()

{

int sum = 0;

for (int i = 1; i <= 500; i++)

{

if (i % 7 == 0)

{

sum += i;

}

}

printf("%d\n", sum);

system("pause");

return 0;

}

---

---

---

#include<stdio.h>

#include<stdlib.h>

int main()

{

int sum_odd = 0, sum_even = 0;

for (int i = 1; i <= 100; i++)

{

if (i % 2 == 0)

{

sum_even += i;

}

else

{

sum_odd += i;

}

}

printf("奇数之和：%d\n偶数之和：%d\n", sum_odd, sum_even);

system("pause");

return 0;

}