Question

C语言：编程输入正整数m和n(m<=n)，求S=1/m+1/(m+1)+1/(m+2)+…+1/(n-1)+1/n。结果保留10位小数，咋写？

Answer 1

代码文本：

#include "stdio.h"

int main(int argc,char *argv[]){

double s;

int m,n;

printf("Enter m & n(int 0<m<=n)...\n");

if(scanf("%d%d",&m,&n)==2 && m>0 && n>=m){

if(n-m>3)

printf("1/%d+1/%d+1/%d+...+1/%d",m,m+1,m+2,n);

else if(m+3==n)

printf("1/%d+1/%d+1/%d+1/%d",m,m+1,m+2,m+3);

else if(m+2==n)

printf("1/%d+1/%d+1/%d",m,m+1,m+2);

else if(m+1==n)

printf("1/%d+1/%d",m,m+1);

else if(m==n)

printf("1/%d",m);

for(s=0.0;m<=n;s+=1.0/m++);

printf(" = %.10f\n",s);

}

else

printf("Input error, exit...\n");

return 0;

}

Answer 2

#include <stdio.h>

main()

{

int m,n,i;

double s=0;

scanf("%d%d",&m,&n);

for(i=0;i<=n-m;i++)

s+=1.0/(m+i);

printf("%.10lf\n",s);

}

---

Answer 3

#include <stdio.h>
main( void )
{
int m,n;
double t=0;
scanf("%d%d",&m,&n);
if( m <=0 || m > n )
{

printf("input error!" ) ;

return ;

}
while( m<=n)
t+=1.0/m++;
printf("%.10lf\n",t);
return ;
}