请问这题怎么解(详细计算过程)?
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(5%-i)/(5%-4%)=(0.7835-0.7917)/(0.7835-0.8219)
(5%-i)/(1%)=-0.0082/-0.0384
100(0.05-i)=82/384=41/192
0.05-i=41/19200
i=5/100-41/19200=(960-41)/19200=919/19200=0.04786458333......≈4.78%
(5%-i)/(1%)=-0.0082/-0.0384
100(0.05-i)=82/384=41/192
0.05-i=41/19200
i=5/100-41/19200=(960-41)/19200=919/19200=0.04786458333......≈4.78%
追问
第三步没看懂,麻烦了
追答
等号前:5%=0.05;/1%=/0.01=100
等号后分子分母同乘-10000
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(120000 x(P-15)-500000-778400)x(1-25%)/(120000 XP)x = 1%
(120000 x(P-15)-1278400)x(75%)/(120000 XP)x1 = 1%
(120000 x(P-15)-1278400)x(3/4)/(120000 XP)= 1%
(120000 x(P-15)-1278400)x1/(160000 XP)= 1%
(120000 x(P-15)-1278400)/(160000 XP)= 1%
(75(P-15)-799)/(100便士)=1%
(75(P-15)-799)/P=1
75(P-15)-799=P
75P-75×15-799=P
75P-P-1924=0
74P=1924
P=26
(120000 x(P-15)-1278400)x(75%)/(120000 XP)x1 = 1%
(120000 x(P-15)-1278400)x(3/4)/(120000 XP)= 1%
(120000 x(P-15)-1278400)x1/(160000 XP)= 1%
(120000 x(P-15)-1278400)/(160000 XP)= 1%
(75(P-15)-799)/(100便士)=1%
(75(P-15)-799)/P=1
75(P-15)-799=P
75P-75×15-799=P
75P-P-1924=0
74P=1924
P=26
追问
谢谢回答,但…是不是答错题了?
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