Question

把下列各式分解因式：（1）2ab(a-2)-8b(a-1)(a-2) (2)a(x-1)+b(x-1)-c(1-x)

Answer 1

（1）2ab(a-2)-8b(a-1)(a-2)
=2(a-2)(ab-4ab+4b)
=2(a-2)(4b-3ab)
=2b(a-2)(4-3a)
(2)a(x-1)+b(x-1)-c(1-x)
=a(x-1)+b(x-1)+c(x-1)
=(x-1)(a+b+c)