2x(x一3)=5.8?
2个回答
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计算过程如下:首先,计算4个数值的和:∑Xs = 0.3 + 0.2 + 0.4 + 0.1 = 1然后,计算 lg-1(∑Xs/4):lg-1(∑Xs/4) = lg-1(1/4) = -1其中,lg表示以10为底的对数,即 log10。...
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Expanding the left side of the equation:
2x^2 - 6x = 5.8
Bringing all the terms to one side:
2x^2 - 6x - 5.8 = 0
Using the quadratic formula:
x = (-(-6) ± sqrt((-6)^2 - 4(2)(-5.8))) / (2(2))
x = (6 ± sqrt(60.4)) / 4
x = (3 ± sqrt(15.1)) / 2
Therefore, the two solutions are:
x = (3 + sqrt(15.1)) / 2
x = (3 - sqrt(15.1)) / 2
2x^2 - 6x = 5.8
Bringing all the terms to one side:
2x^2 - 6x - 5.8 = 0
Using the quadratic formula:
x = (-(-6) ± sqrt((-6)^2 - 4(2)(-5.8))) / (2(2))
x = (6 ± sqrt(60.4)) / 4
x = (3 ± sqrt(15.1)) / 2
Therefore, the two solutions are:
x = (3 + sqrt(15.1)) / 2
x = (3 - sqrt(15.1)) / 2
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