10.计算 (2x)/((x+3)(x-3))+1/(3-x)
4个回答
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原式=2x/[(x+3)(x-3)]-1/(x-3)
通分:=2x/[(x+3)(x-3)]-(x+3)/[(x+3)(x-3)]
=[2x-(x+3)]/[(x+3)(x-3)]
=(2x-x-3)/[(x+3)(x-3)]
=(x-3)/[(x+3)(x-3)]
=1/(x+3)
通分:=2x/[(x+3)(x-3)]-(x+3)/[(x+3)(x-3)]
=[2x-(x+3)]/[(x+3)(x-3)]
=(2x-x-3)/[(x+3)(x-3)]
=(x-3)/[(x+3)(x-3)]
=1/(x+3)
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展开全部
计算 (2x)/((x+3)(x-3))+1/(3-x)
(2x)/((x+3)(x-3))+1/(3-x)
= (2x)/((x+3)(x-3))-1/(x-3)
=(2x)/((x+3)(x-3))-(x+3)/(x+3)(x-3)
=(2x-x-3)/(x+3)(x-3)
=(x-3)/(x+3)(x-3)
=1/(x+3)
(2x)/((x+3)(x-3))+1/(3-x)
= (2x)/((x+3)(x-3))-1/(x-3)
=(2x)/((x+3)(x-3))-(x+3)/(x+3)(x-3)
=(2x-x-3)/(x+3)(x-3)
=(x-3)/(x+3)(x-3)
=1/(x+3)
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展开全部
2X/[(X+3)(X-3)]+1/(3-X)
=2X/[(X+3)(X-3)]-1/(X-3)
=2X/[(X+3)(X-3)]-(X+3)/[(X-3)(X+3)]
=(2X-X-3)/[(X-3)(X+3)]
=(X-3)/[(X-3)(X+3)]
=1/(X+3)
=2X/[(X+3)(X-3)]-1/(X-3)
=2X/[(X+3)(X-3)]-(X+3)/[(X-3)(X+3)]
=(2X-X-3)/[(X-3)(X+3)]
=(X-3)/[(X-3)(X+3)]
=1/(X+3)
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