Question

2x-2[x-(4x-1)]=10(x-1)

Answer 1

将等式中的方括号进行展开和化简，可以得到：

2x - 2[x - (4x - 1)] = 10(x - 1)
2x - 2[x - 4x + 1] = 10x - 10
2x - 2[-3x + 1] = 10x - 10
2x + 6x - 2 = 10x - 10
8x - 2 = 10x - 10

接下来将未知量移到等式的一侧，常数移到另一侧，得到：

8x - 2 - 10x = -10
-2x - 2 = -10
-2x = -8
x = 4

因此，原方程的解为x = 4。

Answer 2

2x-2[x-(4x-1)]=10(x-1)
2x-2[x-4x+1]=10(x-1)
2x-2[-3x+1]=10(x-1)
2x+6x-2=10x-10
2x+6x-10x=-10+2
-2x=-8
x=4