Question

用c#编写 用户输入一个月份 返回这个月的天数

例如，用户输入“March", 系统返回”March有31天

要求：1 忽略大小写，如用户输入march,系统仍然返回March有31天
2 不考虑闰年

Answer 1

可以直接用DateTime.DayInMonth函数来返回指定月份的天数.但只能用数字,不能使用英文.

如果非要用英文来匹配.那就用我写的方法.
public int GetDayInMonth(int year,string MonthName)
{

private string [,] BinMonths =
{
{"1","January"},
{"2","February"},
{"3","March"},
{"4","April"},
{"5","May"},
{"6","June"},
{"7","July"},
{"8","August"},
{"9","September"},
{"10","October"},
{"11","November"},
{"12","December"},
};

for(int i = 0; i < BinMonths.Length; i++ )
{
if(MonthName.Trim().ToLower() == BinMonths[i,1].Trim().ToLower())
{
return DateTime.DaysInMonth(year,int.Parse(BinMonths[i,0]));
}
}
return 0;
}
//ps:我觉得必须输入年份才行,如果楼主觉得没必要,那就把参数int year改成一个数字就可以了.

Answer 2

using System;
using System.Collections.Generic;
using System.Text;

namespace cs_test1
{
class Program
{
static void kk(string s)
{
int day = 0;
string s1=s.ToLower();
switch (s1)
{
case "january":
case "march":
case "may":
case "july":
case "august":
case "october":
case "december":
day = 31;
break;
case "february":
day = 28;
break;
case "april":
case "june":
case "september":
case "november":
day = 30;
break;
default:
day = -1;
break;
}
if (day != -1)
{
Console.WriteLine(s + "一共有" + day + "天");
}
else
{
Console.WriteLine("输入月份错误");
}
}
static void Main(string[] args)
{
Console.WriteLine("输入月份");
kk(Console.ReadLine());
}
}
}

Answer 3

private string getDays(string strMonth)
{
strMonth = strMonth.Substring(0, 1).ToUpper() + strMonth.Substring(1, strMonth.Length - 1).ToLower();
string strMsg = strMonth;
switch (strMonth)
{
case "February":
strMsg += "有28天";
break;
case "January":
case "March":
case "May":
case "July":
case "August":
case "October":
case "December":
strMsg += "有31天";
break;
case "April":
case "June":
case "September":
case "November":
strMsg += "有30天";
break;
default:
strMsg += "输入有误";
break;
}
return strMsg;
}

Answer 4

有自带函数可以用的，孩子