Question

请帮把此程序cout 改成scanf

#include<iostream>
using namespace std;
main()
{ double x,y;
cout<<"请输入一个值X:\n"<<"x=";
cin>>x;
if(x<0&&x!=3) y=x*x+x-6;
else if(x>=0&&x<10&&x!=2&&x!=3) y=x*x-5*x+6;
else y=x*x-x-1;
cout<<"y="<<y<<endl;
}

请把cout 改为scanf ``谢谢

Answer 1

#include<iostream>
#include<stdio.h>
using namespace std;
main()
{ double x,y;
cout<<"请输入一个值X:\n"<<"x=";
scanf("%d",x);
if(x<0&&x!=3) y=x*x+x-6;
else if(x>=0&&x<10&&x!=2&&x!=3) y=x*x-5*x+6;
else y=x*x-x-1;
cout<<"y="<<y<<endl;
}

Answer 2

#include<iostream>
#include<stdio.h>
using namespace std;
main()
{ double x,y;
printf("<<"请输入一个值X:\nx=");//cout<<"请输入一个值X:\n"<<"x=";
cin>>x;
if(x<0&&x!=3) y=x*x+x-6;
else if(x>=0&&x<10&&x!=2&&x!=3) y=x*x-5*x+6;
else y=x*x-x-1;
printf("y=%ld",y);//cout<<"y="<<y<<endl;
}