Question

一道初一的一元一次解方程(关于去分母)

5y+4/3 + y-1/4 = 2- 5y-5/12

最好有过程..

Answer 1

5y+4/3 + y-1/4 = 2- 5y-5/12
两边同时乘12
60y+16+12y-3=24-60y-5
72y+13=19-60y
72y+60y=19-13
132y=6
y=1/22

Answer 2

分母3,4,12的最小公倍数为12,所以等式两边同时乘以12,有:

60y+16+12y-3=24-60y-5

移项并合并同类项有:

(60+60+12)y=24-5-16+3
132y=6
y=1/22

Answer 3

答：5y+4/3 + y-1/4 = 2- 5y-5/12
6y+2/4=19/12-5y
移项得6y+5y=19/12-2/4
11y=13/12
所以y=13/132 !!!^_^

Answer 4

5y+4/3 + y-1/4 = 2- 5y-5/12
5y+y+5y=2-5/12+1/4-4/3
11y=1/2
y=1/22

Answer 5

方程左右两边乘以12
即，60y+16+12Y-3=24-60y-5
72y+13=19-60y
72y+60y=19-13
132y=6
y=1/22

Answer 6

5y+4/3 + y-1/4 = 2- 5y-5/12
6Y+1/2=19/12-5Y
6Y+5Y=19/12-1/2
11Y=13/12
Y=13/132