Question

已知|2a-b+1|+(3a+3/2b)^2=0求b^2/a+b/{(a/a-b-1)(a-a^2/a+b)}

已知|2a-b+1|+(3a+3/2b)^2=0求b^2/a+b / {(a/a-b -1)(a- a^2/a+b)}

Answer 1

|2a-b+1|+(3a+3/2b)^2=0
绝对值和平方都大于等于0
现在相加等于0
若有一个大于0，则另一个小于0，不可能
所以两个都等于0
所以2a-b+1=0
3a+3b/2=0
b=2a+1
3a+3a+3/2=0
a=-1/4
b=1/2

代入所要求的式子即可，你写的符号我看不懂，你自己算吧

Answer 2

|2a-b+1|+(3a+3/2b)^2=0
|2a-b+1|=0
2a-b+1=0.........1

(3a+3/2b)^2=0
(3a+3/2b)^2=0
3a+3/2b=0
a+1/2b=0
a=-b/2.........2

将2式代入1式得
2(-b/2)-b+1=0
-2b+1=0
b=1/2

a=-b/2=(-1/2)/2=-1/4

b^2/a+b / {(a/a-b -1)(a- a^2/a+b)} ????????

Answer 3

think by yourself