Question

C# WinForm中有关txt文件读取的问题

例如：有个文本文件内容如下：
XXXXXXXXXXXXaaa
XXXXXXXXXXXXbbb
XXXXXXXXXXXXXXXXXXaaaXXX
XXXXXXX ccc
XXXXXXXXXXXXX aaa

如何取出上面文本中带aaa的行，以及有多少行，在textbox中显示出来。
希望能给出代码，先谢谢了！

Answer 1

用流可以一行一行的读。每读到一行++，就行了！
using System.IO;
using System.Text;

int count = 0;
FileStream fs = new FileStream("E:\\1.txt", FileMode.Open, FileAccess.Read);
StreamReader sr = new StreamReader(fs, Encoding.GetEncoding("GB2312"));
string line = sr.ReadLine();
for (int i = 0; line != null; i++)
{
if (line.Contains("a") == true)
{
count++;
TextBox1.Text += line;
}
line = sr.ReadLine();
}
Response.Write(count);
sr.Close();
fs.Close();

不懂在HI我吧

Answer 2

OpenFileDialog loOpenFile = new OpenFileDialog();
if (loOpenFile.ShowDialog() == DialogResult.OK)
{
FileStream fs = new FileStream(loOpenFile.FileName,FileMode.Open);
StreamReader sr = new StreamReader(fs);
string an=sr.ReadLine();
int tatle = 0;
while (an!= null)
{
if(an.IndexOf("a")>0)
{
TextBox1.Text = TextBox1.Text + an + "\n";
tatle++;
}
an = sr.ReadLine();
}
sr.Close();
fs.Close();
this.Text = "行含有a字母的行一共有"tatle+"行"
}