Question

用java编程实现获取一个四位数的各个位的和！

Answer 1

import java.util.Scanner;
class Test
{
public static void main(String[] args)
{
Scanner a1 = new Scanner(System.in);
System.out.print("请输入数字： ");
int num = a1.nextInt();
int b1 = num/1000;
int b2 = (num-b1*1000)/100;
int b3 = (num-b1*1000-b2*100)/10;
int b4 = (num-b1*1000-b2*100-b3*10)/1;
int sum = b1+b2+b3+b4;
System.out.println("各个位的和是 " + sum);
}
}
比较通俗易懂的程序。呵呵。。。
也可以设置一下输入位数的个数。

Answer 2

public int mySum(int number){
int i = number / 1000;
int j = (number - i*1000) / 100;
int k = (number -i*1000 - j*100)/ 10;
int l = number - i*1000 - j*100 - k*10;
int count = i +j + k + l;
return count;
}

Answer 3

http://zhidao.baidu.com/question/148811465.html

这里

其中二楼答案有些乱应该为
public int sum(int number) {
String s = String.valueOf(number);
int su = 0;
for (int i = 0; i < s.length(); i++) {
su += s.charAt(i) - 48;
}
return su;
}