Question

vc6.0 程序编译出现错误 怎么回事

源程序如下：
#include <stdio.h>
#define M 5
#define N 5

int main(void)
{

int a[M,N];
int b[M,N];
int c[M,N];
int i,j,m,n,t,k,p;

printf("Please enter the number m & n:");
scanf("%d %d",&m,&n);

printf("Please enter the first Array:");
for ( i = 0;i <= m;i ++)
{
for (j =0;j <= n;j ++)
{
scanf("%d",&a[i,j]);
}
}

printf("Please enter the second Array:");
for (i = 0;i <= m;i ++)
{
for (j = 0;j <= n;j ++)
{
scanf("%d",&b[i,j]);
}
}

printf("Please enter the third Array:");
for (i = 0;i <= m;i ++)
{
for (j = 0;j <= n;j ++)
{
scanf("%d",&c[i,j]);
}
}

printf("Please enter the number k & p:");
scanf("%d %d",&k,&p);

switch(p)
{
case 1:
for (i = 0;i <= m;i ++)
{
for (j = 0;j <=n;j ++)
{

printf("%d",k*a[i,j]);

}

printf("\n");

}
break; //矩阵的数乘

case 2:
for (i = 0;i <= m;i++)
{
for (j = 0;j <=n;j++)
{
printf("%d",b[j,i]);
}
printf("\n");
}
break; // 这个程序不对

case 3:
for (i = 0;i <= m;i ++)
{
for (j = 0;j <= n;j++)
{
printf("%d",b[i,j] + c[i,j]);
}
printf("\n");
}
break; //矩阵的加法

case 4:
for (i = 0;i <= m;i ++)
{
for (j = 0;j <= n;j ++)
{
printf("%d",b[i,j] - c[i,j]);
}
printf("\n");
}
break; //矩阵的减法

case 5:
for (i = 0;i <= m;i ++)
{
for (j = 0;j <=n;j++)
{
printf("%d",b[i,j] * c[i,j]);
}
printf("\n");
}
break; //矩阵的乘法

default:
printf("Input error!\n");
}

}

出现错误：
G:\C语言\20100420.c(8) : error C2143: syntax error : missing ']' before ','
G:\C语言\20100420.c(8) : error C2059: syntax error : 'constant'
G:\C语言\20100420.c(9) : error C2143: syntax error : missing ']' before ','
G:\C语言\20100420.c(9) : error C2059: syntax error : 'constant'
G:\C语言\20100420.c(10) : error C2143: syntax error : missing ']' before ','
G:\C语言\20100420.c(10) : error C2059: syntax error : 'constant'

Answer 1

#include <stdio.h>
#define M 5
#define N 5

int main(void)
{

int a[M][N];
int b[M][N];
int c[M][N];
int i,j,m,n,t,k,p;

printf("Please enter the number m & n:");
scanf("%d %d",&m,&n);

printf("Please enter the first Array:");
for ( i = 0;i < m;i++)
{
for (j =0;j < n;j ++)
{
scanf("%d",&a[i][j]);
}
}

printf("Please enter the second Array:");
for (i = 0;i < m;i ++)
{
for (j = 0;j < n;j ++)
{
scanf("%d",&b[i][j]);
}
}

printf("Please enter the third Array:");
for (i = 0;i < m;i ++)
{
for (j = 0;j < n;j ++)
{
scanf("%d",&c[i][j]);
}
}

printf("Please enter the number k & p:");
scanf("%d %d",&k,&p);

switch(p)
{
case 1:
for (i = 0;i < m;i ++)
{
for (j = 0;j <n;j ++)
{

printf("%d",k*a[i][j]);

}

printf("\n");

}
break; //矩阵的数乘

case 2:
for (i = 0;i < m;i++)
{
for (j = 0;j <n;j++)
{
printf("%d",b[j][i]);
}
printf("\n");
}
break; // 这个程序不对

case 3:
for (i = 0;i < m;i ++)
{
for (j = 0;j < n;j++)
{
printf("%d",b[i][j] + c[i][j]);
}
printf("\n");
}
break; //矩阵的加法

case 4:
for (i = 0;i < m;i ++)
{
for (j = 0;j < n;j ++)
{
printf("%d",b[i][j] - c[i][j]);
}
printf("\n");
}
break; //矩阵的减法

case 5:
for (i = 0;i < m;i ++)
{
for (j = 0;j <n;j++)
{
printf("%d",b[i][j] * c[i][j]);
}
printf("\n");
}
break; //矩阵的乘法

default:
printf("Input error!\n");
}

}
你的二维数组定义和表示错了，应该是array[][]。还有数组的下标是从0开始的，比如一个二维数组a[3][3]它的元素个数为9个分别为a[0][0],a[0][1],a[0][2],a[1][0],a[1][1],a[1][2],a[2][0],a[2][1],a[2][2]。你在输入和输出时用了<=就错了，要用<。

Answer 2

#include <stdio.h>
#define M 5
#define N 5

int main(void)
{

int a[M][N];
int b[M][N];
int c[M][N];
int i,j,m,n,k,p;

printf("Please enter the number m & n:");
scanf("%d %d",&m,&n);

printf("Please enter the first Array:");
for ( i = 0;i <= m;i ++)
{
for (j =0;j <= n;j ++)
{
scanf("%d",&a[i][j]);
}
}

printf("Please enter the second Array:");
for (i = 0;i <= m;i ++)
{
for (j = 0;j <= n;j ++)
{
scanf("%d",&b[i][j]);
}
}

printf("Please enter the third Array:");
for (i = 0;i <= m;i ++)
{
for (j = 0;j <= n;j ++)
{
scanf("%d",&c[i][j]);
}
}

printf("Please enter the number k & p:");
scanf("%d %d",&k,&p);

switch(p)
{
case 1:
for (i = 0;i <= m;i ++)
{
for (j = 0;j <=n;j ++)
{

printf("%d",k*a[i][j]);

}

printf("\n");

}
break; //矩阵的数乘

case 2:
for (i = 0;i <= m;i++)
{
for (j = 0;j <=n;j++)
{
printf("%d",b[j][i]);
}
printf("\n");
}
break; // 这个程序不对

case 3:
for (i = 0;i <= m;i ++)
{
for (j = 0;j <= n;j++)
{
printf("%d",b[i][j] + c[i][j]);
}
printf("\n");
}
break; //矩阵的加法

case 4:
for (i = 0;i <= m;i ++)
{
for (j = 0;j <= n;j ++)
{
printf("%d",b[i][j] - c[i][j]);
}
printf("\n");
}
break; //矩阵的减法

case 5:
for (i = 0;i <= m;i ++)
{
for (j = 0;j <=n;j++)
{
printf("%d",b[i][j] * c[i][j]);
}
printf("\n");
}
break; //矩阵的乘法

default:
printf("Input error!\n");
}
你上面的问题全出在二维数组的定义上面，二维数组定义为data[][]形式，而不是你的那样。

Answer 3

#include <stdio.h>
#define M 5
#define N 5

int main(void)
{

int a[M][N];
int b[M][N];
int c[M][N];
int i,j,m,n,t,k,p;

printf("Please enter the number m & n:");
scanf("%d %d",&m,&n);

printf("Please enter the first Array:");
for ( i = 0;i <= m;i ++)
{
for (j =0;j <= n;j ++)
{
scanf("%d",&a[i,j]);
}
}

printf("Please enter the second Array:");
for (i = 0;i <= m;i ++)
{
for (j = 0;j <= n;j ++)
{
scanf("%d",&b[i,j]);
}
}

printf("Please enter the third Array:");
for (i = 0;i <= m;i ++)
{
for (j = 0;j <= n;j ++)
{
scanf("%d",&c[i,j]);
}
}

printf("Please enter the number k & p:");
scanf("%d %d",&k,&p);

switch(p)
{
case 1:
for (i = 0;i <= m;i ++)
{
for (j = 0;j <=n;j ++)
{

printf("%d",k*a[i][j]);

}

printf("\n");

}
break; //矩阵的数乘

case 2:
for (i = 0;i <= m;i++)
{
for (j = 0;j <=n;j++)
{
printf("%d",b[j][i]);
}
printf("\n");
}
break; // 这个程序不对

case 3:
for (i = 0;i <= m;i ++)
{
for (j = 0;j <= n;j++)
{
printf("%d",b[i][j] + c[i][j]);
}
printf("\n");
}
break; //矩阵的加法

case 4:
for (i = 0;i <= m;i ++)
{
for (j = 0;j <= n;j ++)
{
printf("%d",b[i][j] - c[i][j]);
}
printf("\n");
}
break; //矩阵的减法

case 5:
for (i = 0;i <= m;i ++)
{
for (j = 0;j <=n;j++)
{
printf("%d",b[i][j] * c[i][j]);
}
printf("\n");
}
break; //矩阵的乘法

default:
printf("Input error!\n");
}

}

Answer 4

唔……我帮你改好了，以下程序可行。
#include <stdio.h>
#include <iostream>
using namespace std;
#define M 5
#define N 5

void main()
{

int a[M][N];
int b[M][N];
int c[M][N];
int i,j,m,n,k,p;

printf("Please enter the number m & n:");
scanf("%d %d",&m,&n);

printf("Please enter the first Array:");
for ( i = 0;i <= m;i ++)
{
for (j =0;j <= n;j ++)
{
scanf("%d",&a[i,j]);
}
}

printf("Please enter the second Array:");
for (i = 0;i <= m;i ++)
{
for (j = 0;j <= n;j ++)
{
scanf("%d",&b[i,j]);
}
}

printf("Please enter the third Array:");
for (i = 0;i <= m;i ++)
{
for (j = 0;j <= n;j ++)
{
scanf("%d",&c[i,j]);
}
}

printf("Please enter the number k & p:");
scanf("%d %d",&k,&p);

switch(p)
{
case 1:
for (i = 0;i <= m;i ++)
{
for (j = 0;j <=n;j ++)
{

printf("%d",k*a[i][j]);

}

printf("\n");

}
break; //矩阵的数乘

case 2:
for (i = 0;i <= m;i++)
{
for (j = 0;j <=n;j++)
{
printf("%d",b[j][i]);
}
printf("\n");
}
break; // 这个程序不对

case 3:
for (i = 0;i <= m;i ++)
{
for (j = 0;j <= n;j++)
{
printf("%d",b[i][j] + c[i][j]);
}
printf("\n");
}
break; //矩阵的加法

case 4:
for (i = 0;i <= m;i ++)
{
for (j = 0;j <= n;j ++)
{
printf("%d",b[i][j] - c[i][j]);
}
printf("\n");
}
break; //矩阵的减法

case 5:
for (i = 0;i <= m;i ++)
{
for (j = 0;j <=n;j++)
{
printf("%d",b[i][j] * c[i][j]);
}
printf("\n");
}
break; //矩阵的乘法

default:
printf("Input error!\n");
}

}