求学霸指点！！！
3个回答
展开全部
(x+y+z)(-x+y+z)(x-y+z)(x+y-z)
=[x+（y+z）] [(y+z）-x] [x-（y-z)] [x+（y-z)]
=[(y+z）²-x²][x²-（y-z）²]
=(y+z）²x²-(y+z）²（y-z）²-x⁴+x²（y-z）²
=x²[(y+z）²+（y-z）²]-（y²-z²）²-x⁴
=x²（2y²+2z²）-y⁴+2y²z²-z⁴-x⁴
=-x⁴-y⁴-z⁴+2x²y²+2x²z²+2y²z²
=[x+（y+z）] [(y+z）-x] [x-（y-z)] [x+（y-z)]
=[(y+z）²-x²][x²-（y-z）²]
=(y+z）²x²-(y+z）²（y-z）²-x⁴+x²（y-z）²
=x²[(y+z）²+（y-z）²]-（y²-z²）²-x⁴
=x²（2y²+2z²）-y⁴+2y²z²-z⁴-x⁴
=-x⁴-y⁴-z⁴+2x²y²+2x²z²+2y²z²
追答
采纳一下吧
本回答由提问者推荐
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
