Question

把下列各式因式分解

5（a-b)²+10(b-a)=
2(a-b)³-4（b-a)²=
（x+y)(x+3)-(y+x)(x+5)=
(2x-y)(3x+2)-(y-2x)(3x-1)

Answer 1

6x的三次方y(x-y)的三次方-4xy的三次方(y-x)的二次方

=6x^3y(x-y)^3-4xy^3(y-x)^2

=6x^3y(x-y)^3-4xy^3(x-y)^2
=2xy(x-y)^2[3x^2(x-y)-2y^2]
=2xy(x-y)^2[3x^3-3x^2y-2y^2]

Answer 2

1、原式＝﹙a－b﹚[5﹙a－b﹚－10]＝5﹙a－b﹚﹙a－b－2﹚
2、原式＝2﹙a－b﹚²﹙a－b－2﹚
3、原式＝﹙x＋y﹚﹙x＋3－x－5﹚＝－2﹙x＋y﹚
4、原式＝﹙2x－y﹚﹙3x＋2＋3x－1﹚＝﹙2x－y﹚﹙6x＋1﹚

Answer 3

5（a-b)(a-b-2)

2(a-b)²(a-b-2)

-2（x+y)

(2x-y)(6x-1)

Answer 4

第一个，（5b-5a)(b-a+2)