Question

满足条件1+2+3+4+····n>=1000最小n及s的值用C语言编程

Answer 1

#include<stdio.h>
main()
{
int n;
int s=0;
for(n=1;;n++)
{
s+=n;
if(s>=1000)
break;
}
printf("n=%d,s=%d",n,s);
}
我运行了，没错误。结果为:n=45,s=1035

Answer 2

#include<iostream.h>
void main()
{
int i,s=0,n=1;
while(1)
{
s+=n;
if(s>=1000)
break;
n++;
}
cout<<"n="<<n<<' '<<"s="<<s<<endl;
}

结果：n=45,s=1035

Answer 3

#include <stdio.h>
int main()
{
int n=1,s=1;
do
{
n=n+1;
s=s+n;
} while (s<=1000);
printf("%d %d",n,s);
}

结果：n=45,s=1035

Answer 4

来运行个简单的程序
#include <stdio.h>
void main()
{
int s=0,i=1;

while(s<1000)
{
s+=i;
i++;
}
printf("%d\t%d",s,i-1);

}

Answer 5

#include<stdio.h>
void main()
{
int n=0;
int s=0;
for(;s<1000;)
{n++;
s+=n;
}
printf("%d,%d",n,s);
}
结果：45，1035