Question

c++如何使创建的窗口大小不可以改变的源代码

Answer 1

C++中当窗口大小改变的时候，系统就会发送一个WM_SIZE消息，如果你不想改变窗口的大小，就截获该消息并且不进行任何处理即可。
对于C++程序，你可以在消息处理函数这样写
LRESULT CALLBACK WindowProc(HWND hwnd,
UINT uMsg,
WPARAM wParam,
LPARAM lParam){
switch(uMsg){
case WM_SIZE:
break;
}
对于MFC程序，你可以在响应WM_SIZE消息的消息处理函数中处理。

Answer 2

#include <windows.h>

LRESULT CALLBACK WndProc (HWND, UINT, WPARAM, LPARAM) ;

int WINAPI WinMain (HINSTANCE hInstance, HINSTANCE hPrevInstance,

PSTR szCmdLine, int iCmdShow)

{

static TCHAR szAppName[] = TEXT ("HelloWin") ;

HWND hwnd ;

MSG msg ;

WNDCLASS wndclass ;

wndclass.style = CS_HREDRAW | CS_VREDRAW ;

wndclass.lpfnWndProc = WndProc ;

wndclass.cbClsExtra = 0 ;

wndclass.cbWndExtra = 0 ;

wndclass.hInstance = hInstance ;

wndclass.hIcon = LoadIcon (NULL, IDI_APPLICATION) ;

wndclass.hCursor = LoadCursor (NULL, IDC_ARROW) ;

wndclass.hbrBackground= (HBRUSH) GetStockObject (WHITE_BRUSH) ;

wndclass.lpszMenuName = NULL ;

wndclass.lpszClassName= szAppName ;

if (!RegisterClass (&wndclass))

{

MessageBox ( NULL, TEXT ("This program requires Windows NT!"),

szAppName, MB_ICONERROR) ;

return 0 ;

}

hwnd = CreateWindow( szAppName, // window class name

TEXT ("The Hello Program"), // window caption

WS_OVERLAPPEDWINDOW&~WS_THICKFRAME, // window style

CW_USEDEFAULT,// initial x position

CW_USEDEFAULT,// initial y position

CW_USEDEFAULT,// initial x size

CW_USEDEFAULT,// initial y size

NULL, // parent window handle

NULL, // window menu handle

hInstance, // program instance handle

NULL) ; // creation parameters

ShowWindow (hwnd, iCmdShow) ;

UpdateWindow (hwnd) ;

while (GetMessage (&msg, NULL, 0, 0))

{

TranslateMessage (&msg) ;

DispatchMessage (&msg) ;

}

return msg.wParam ;

}

LRESULT CALLBACK WndProc (HWND hwnd, UINT message, WPARAM wParam, LPARAM lParam)

{
switch (message)
{
case WM_DESTROY:

PostQuitMessage (0) ;

return 0 ;
}

return DefWindowProc (hwnd, message, wParam, lParam) ;

}
程序如上，很简单就是创建窗口的时候，样式写成
WS_OVERLAPPEDWINDOW&~WS_THICKFRAME
这个就可以了。