Question

Python爬虫怎么抓取html网页的代码块

比如在这段代码中，我想抓取table align="center" border=7 class="base_index">到<td width="25%" class="head_td top_bottom"><a href="MinGe/Index.htm">民歌民乐</a></td>的内容，先不考虑编码的问题，为什么我用body = re.findall('<table align="center" border=7 class="base_index">(.*?)<td width="25%" class="head_td top_bottom"><a href="MinGe/Index.htm">',code,re.S)抓取之后输出的是一个list元组呢？

Answer 1

mport urllib.request
import re

def getHtml(url):
page = urllib.request.urlopen(url)
html = page.read()
html = html.decode('GBK')
return html

def getMeg(html):
reg = re.compile(r'******')
meglist = re.findall(reg,html)
for meg in meglist:
with open('out.txt',mode='a',encoding='utf-8') as file:
file.write('%s\n' % meg)

if __name__ == "__main__":
html = getHtml(url)
getMeg(html)

Answer 2

范围匹配大点，像这种

re.findall('(<div class="moco-course-wrap".*?</div>)',source,re.S)

可以看下这个

http://blog.csdn.net/tangdou5682/article/details/52596863