Question

26题求解要过程

Answer 1

1)M是圆心
2)设半径=R,OM=R-OA=R-2
∵RT△AGM≌RT△COM(AAS)
∴OC=AG,MF=OM
∴OC=AG=1/2*AD=1/2*8=4
∴OC=4
∵OM^2+OC^2=MC^2
(R-2)^2+4^2=R^2
R=5
OM=5-2=3
∵RT△AOF相似于RT△AGM
OF/MF=OA/AG
OF/3=2/4
OF=3/2=1.5
F(0,1.5)
3)∵RT△COM相似于RT△CMP
∴MC/PM=OM/MC ,∠QMO=∠QMP
∴MC^2=OM*PM

PM=MC^2/OM=5^2/3=25/3
∴PM=25/3
又MQ/OM=5/3,PM/MQ=(25/3)/5=5/3
∴MQ/OM=PM/MQ=5/3
∵MQ/OM=PM/MQ,∠QMO=∠QMP
∴△QOM相似于△QMP
4)∵△QOM相似于△QMP
∴OQ/PQ=QM/PM
∴OQ/PQ=5/(25/3)=3/5
∴OQ/PQ=3/5