u∧4-2u∧3-2u-1因式分解
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是为了积分吧?
(1-u+u^2)/(3u^2-2u-u^3)
=(1-u+u^2)/u(3u-2-u^2)
=(-1+u-u^2)/u(u-1)(u-2)
=(设为)=a/u+b/(u-1)+c/(u-2)
再通分
=[a(u-1)+bu]/u(u-1)+c/(u-2)
={[a(u-1)+bu](u-2)+cu(u-1)}/u(u-1)(u-2)
把大括号里的东西乘出来,令其恒等于-1+u-u^2（即所有系数相等）即可.
(1-u+u^2)/(3u^2-2u-u^3)
=(1-u+u^2)/u(3u-2-u^2)
=(-1+u-u^2)/u(u-1)(u-2)
=(设为)=a/u+b/(u-1)+c/(u-2)
再通分
=[a(u-1)+bu]/u(u-1)+c/(u-2)
={[a(u-1)+bu](u-2)+cu(u-1)}/u(u-1)(u-2)
把大括号里的东西乘出来,令其恒等于-1+u-u^2（即所有系数相等）即可.
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