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(1)
不妨令d/a = x
"1"上面的一行变为：(1 + x)² = 1 + 2x
1 + 2x + x² = 1 + 2x
x² = 0, x = d/a = 0
(2)中两式同除以a:
1 + d/a = q², 1 + 2d/a = q
1 + d/a = (1 + 2d/a)² = 1 + 4d/a + 4(d/a)²
4(d/a)² + 3d/a = 0
(d/a)(4d/a + 3) = 0
d/a = 0或 d/a = -3/4
d/a = 0时，1 + 2d/a = 1 + 0 = 1 = q
d/a = -3/4时, 1 - 2*3/4 = q = -1/2
不妨令d/a = x
"1"上面的一行变为：(1 + x)² = 1 + 2x
1 + 2x + x² = 1 + 2x
x² = 0, x = d/a = 0
(2)中两式同除以a:
1 + d/a = q², 1 + 2d/a = q
1 + d/a = (1 + 2d/a)² = 1 + 4d/a + 4(d/a)²
4(d/a)² + 3d/a = 0
(d/a)(4d/a + 3) = 0
d/a = 0或 d/a = -3/4
d/a = 0时，1 + 2d/a = 1 + 0 = 1 = q
d/a = -3/4时, 1 - 2*3/4 = q = -1/2
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