Question

用java去掉字符串中重复的空格怎么写啊

比如字符串"aa bb cc dd"处理后结果为"aa bb cc dd"

Answer 1

public class test {
public static void main(String[] args) {
String str = "aa bb cc dd ee cs ";
String s = "";
for (int i = 0; i < str.length() - 1; i++) {
if ((int) str.charAt(i) == 32 && (int) str.charAt(i + 1) == 32) {
continue;
}
s += str.charAt(i);
}
if ((int) str.charAt(str.length() - 1) != 32)
s += str.charAt(str.length() - 1);
System.out.println(s);
}
}

Answer 2

不用那么麻烦，用正则表达式很简单
public static void main(String args[])
{
String str = "aa bb cc dd";
String test = str.replaceAll("\\s{1,}", " ");
System.out.println(test);
}
把所有多于1个的空格替换成1个空格

Answer 3

public class TestString01 {
public static void main(String[] args) {
String str = "aa bb cc dd";
/*String s1[] = str.split(" ");
for(int i=0;i<s1.length;i++){
System.out.print(s1[i]);
}*/
String s1 = str.replaceAll("aa bb cc dd", "aabbccdd");
System.out.println(s1);
}
}

Answer 4

static String begin(String s)
{
int i=0;String news="";
while(i<s.length())
{
if(s.charAt(i)!=' ')new s+=s.charAt(i);
i++
}
return news;
}