Question

python简单的并发问题

请问：1.为什么打印的时候1会和XYZ粘在一起？为什么会打印空行？2.首先同时执行3次func，那么剩余的两次会在什么时候执行？这两次可以在for循环的任意时机执行吗？

Answer 1

• #!/usr/bin/envpython#-*-coding:utf-8-*-#author:ChanghuaGongimporttime,threading#fromurllib.requestimportRequest,urlopenpy3#fromurllib.errorimportURLErrorpy3importurllib2#URLreq=urllib2.Request('http://47.93.169.69:10080/pigeon-web/user/user

• #!/usr/bin/env python

  # -*- coding:utf-8 -*-

  # author: Changhua Gong

  import time,threading

  # from urllib.request import Request, urlopen py3

  # from urllib.error import URLError py3

  import urllib2

  #URL

  req = urllib2.Request('http://47.93.169.69:10080/pigeon-web/user/userExtraInfo?userId=1')

  #

  rule = {0:500,1:30}

  '''

  Rule规则:0:50,第一次运行不睡眠即为0,直接并发50次;1:20,第二秒,相当于睡眠1秒,然后并发20次,

  如第三秒需并发500次,则rule = {0:50,1:20,1:500}

  '''

  #Open url

  def geturl():

  time_b = time.time()

  try:

  response = urllib2.urlopen(req)

  print(response.read().decode("utf-8")) # 打印输出内容

  except urllib2.URLError as e:

  if hasattr(e, 'reason'):

  print('We failed to reach a server.')

  print('Reason: ', e.reason)

  elif hasattr(e, 'code'):

  print('The server couldn/'t fulfill the request.')

  print('Error code: ', e.code)

  time_e = time.time()

  print("Thread %s runned for %ss" % (threading.current_thread().name, (time_e - time_b))) #线程访问时效

  if __name__=='__main__':

  for k in rule:

  time.sleep(k)

  for i in range(rule[k]):

  t = threading.Thread(target=geturl)

  t.start()