Question

解下列分式方程:(1)X/(X-2)+(X-9)/(X-7)=(X+1)/(X-1)+(X-8)/(X-6)(2)

Answer 1

1.x/(x-2)=1+2/(x-2)
x-9/(x-7)=
1-2/(x-7)
x+1/(x-1)=1+2/(x-1)
x-8/(x-6)=1-2/(x-6)
代入得1/(x-2)-1/(x-7)=1/(x-1)-1/(x-6)
移项得1/(x-2)+1/(x-6)=1/(x-1)+1/(x-7)
然后通分就好算了，注意x不等于1,2,6,7(分母不为0),最后要作为增根消去.
2.方法类似上一题,都是先写成1+一个分数的形式,然后移项后再通分