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请问这道题用换元法怎么解?
1个回答
展开全部
f(x+1/空早敏斗枝睁闹x )
=x^2/(x^4+1)
分子分母同时除x^2
=1/ ( x^2 +1/x^2)
=1/[ (x+1/x)^2 -2]
ie
f(x) = 1/(x^2-2)
=x^2/(x^4+1)
分子分母同时除x^2
=1/ ( x^2 +1/x^2)
=1/[ (x+1/x)^2 -2]
ie
f(x) = 1/(x^2-2)
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