Question

某商店以每件300元卖出两种不同的商品，一件赚20%，一件亏20%总的来说亏多少元 求讲解，方法，急

Answer 1

zdc3096 | 十八级 最快回答
设进价分别为A元和B元
(300-A)/A=20%
A=250
（B-300)/B=20%
B=375
进价合计250+375=625元
售价合计600元
亏损625-600=25元评论 | 给力2不给力0if(typeof PDC != 'undefined'){PDC.tti();}知道日报2014.1.2往期回顾 汽车尾气只占北京市PM2.5来源的4%吗？登录 还没有百度账号？立即注册
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Answer 2

因为售价相同，第一件就是有（300-进价）/进价=20%，所以第一件进价300÷1.2=250元，赚了50元。
第二件亏了20%，就是（进价-300）/进价=20%，进价=300÷0.8=375元，亏了75元。所以一共亏了75-50=25元。

Answer 3

赚20％的商品进价300÷(1+20％)=250元
亏20％的商品进价300÷(1-20％)=375元
(375+250)-2×300=25元
答:总的来说亏25元。