x∧4-6x∧2-3+x+2因式分解？
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x^4 - 6x^2 - 3x + 2
= x^4 + x^3 - x^3 - x^2 - 5x^2 - 5x + 2x + 2
= x^3(x+1)-x^2(x+1)-5x(x+1)+2(x+1)
= (x+1)(x^3-x^2-5x+2)
= (x+1)(x^3+2x^2-3x^2-6x+x+2)
= (x+1)[(x^2(x+2)-3x(x+2)+(x+2)]
= (x+1)(x+2)(x^2-3x+1)
= x^4 + x^3 - x^3 - x^2 - 5x^2 - 5x + 2x + 2
= x^3(x+1)-x^2(x+1)-5x(x+1)+2(x+1)
= (x+1)(x^3-x^2-5x+2)
= (x+1)(x^3+2x^2-3x^2-6x+x+2)
= (x+1)[(x^2(x+2)-3x(x+2)+(x+2)]
= (x+1)(x+2)(x^2-3x+1)
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