六分之八加十二分之八加二十分之八加省略号一直加到六百五十分之八等于多少?
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六分之八加十二分之八加二十分之八加省略号一直加到六百五十分之八
=8/6+8/12+8/20+……+8/650
=4/3+4/6+4/10+……+4/325
=4×(1/3+1/6+1/10+…+1/325)
=4×(1/2+1/10+……+1/325)
=4×(3/5+1/15+……+1/325)
=4×(2/3+1/21+……+1/325)
=4×(5/7+1/28+……+1/325)
=4×(3/4+1/36+……+1/325)
…………………………
=4×12/13
=48/13
=8/6+8/12+8/20+……+8/650
=4/3+4/6+4/10+……+4/325
=4×(1/3+1/6+1/10+…+1/325)
=4×(1/2+1/10+……+1/325)
=4×(3/5+1/15+……+1/325)
=4×(2/3+1/21+……+1/325)
=4×(5/7+1/28+……+1/325)
=4×(3/4+1/36+……+1/325)
…………………………
=4×12/13
=48/13
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成为第45位粉丝
1/2+1/4+1/8+……+1/128
解:方法(一)
设原式为A
(1/2+1-4+1/8+1/16+……+1/128)×2为B
B一A得:
(1/2+1/4+1/8+1/16+……+1/128)×2-(1/2+1/4+1/8+1/16+……+1/128)
=1+1/2+1/4+1/8+1/16++……+1/64-1/2-1/4-1/8-1/16-1/32-……-1/128
=1+(1/2-1/2)+(1/4-1/4)+……+(1/64-1/64)-1/128
=1-1/128
=127/128
方法(二)
1/2+1/4+1/8+……+1/64+1/128
=1/2+1/4+1/8+……++1/64+1/128+1/128-1/28
=1/2+1/4+1/8+……1/64+1/64-1/128
=1/2+1/4+1/8+……+1/32+1/32-1/128
=1/2+1/4+1/8+1/16+1/16-1/128
=1/2+1/4+1/8+1/8-1/128
=1/2+1/4+1/4-1/128
=1/2+1/2-1/128
=1-1/128
=127/128
1/2+1/4+1/8+……+1/128
解:方法(一)
设原式为A
(1/2+1-4+1/8+1/16+……+1/128)×2为B
B一A得:
(1/2+1/4+1/8+1/16+……+1/128)×2-(1/2+1/4+1/8+1/16+……+1/128)
=1+1/2+1/4+1/8+1/16++……+1/64-1/2-1/4-1/8-1/16-1/32-……-1/128
=1+(1/2-1/2)+(1/4-1/4)+……+(1/64-1/64)-1/128
=1-1/128
=127/128
方法(二)
1/2+1/4+1/8+……+1/64+1/128
=1/2+1/4+1/8+……++1/64+1/128+1/128-1/28
=1/2+1/4+1/8+……1/64+1/64-1/128
=1/2+1/4+1/8+……+1/32+1/32-1/128
=1/2+1/4+1/8+1/16+1/16-1/128
=1/2+1/4+1/8+1/8-1/128
=1/2+1/4+1/4-1/128
=1/2+1/2-1/128
=1-1/128
=127/128
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