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y=(x-1)*[(3x+1)^(2/3)]*(x-2)
y'=(x-1)'*[(3x+1)^(2/3)]*(x-2)+(x-1)*[(3x+1)^(2/3)]'*(x-2)+(x-1)*[(3x+1)^(2/3)]*(x-2)'
=[(3x+1)^(2/3)]*(x-2)+(x-1)*2[(3x+1)^(-1/3)*(x-2)+(x-1)*[(3x+1)^(2/3)]
y'=(x-1)'*[(3x+1)^(2/3)]*(x-2)+(x-1)*[(3x+1)^(2/3)]'*(x-2)+(x-1)*[(3x+1)^(2/3)]*(x-2)'
=[(3x+1)^(2/3)]*(x-2)+(x-1)*2[(3x+1)^(-1/3)*(x-2)+(x-1)*[(3x+1)^(2/3)]
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