已知实数a、b、c满足a+b+c=0,a2+b2+c2=0.1,则a4+b4+c4的值是
已知实数a、b、c满足a+b+c=0,a2+b2+c2=0.1,则a4+b4+c4的值是______....
已知实数a、b、c满足a+b+c=0,a2+b2+c2=0.1,则a4+b4+c4的值是 ______.
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∵a+b+c=0,
∴(a+b+c)2=a2+b2+c2+2ab+2ac+2bc=0,
∵a2+b2+c2=0.1,
∴2ab+2ac+2bc=-0.1,
∵(2ab+2ac+2bc)2=4(a2b2+a2c2+b2c2+2a2bc+2ab2c+2abc2)=0.01,
∵2a2bc+2ab2c+2abc2=2abc(a+b+c)=0,
∴a2b2+a2c2+b2c2=0.0025①
(a2+b2+c2)2=a4+b4+c4+2(a2b2+a2c2+b2c2)=0.01②
由①②得出,a4+b4+c4=0.005.
故答案为:0.005.
∴(a+b+c)2=a2+b2+c2+2ab+2ac+2bc=0,
∵a2+b2+c2=0.1,
∴2ab+2ac+2bc=-0.1,
∵(2ab+2ac+2bc)2=4(a2b2+a2c2+b2c2+2a2bc+2ab2c+2abc2)=0.01,
∵2a2bc+2ab2c+2abc2=2abc(a+b+c)=0,
∴a2b2+a2c2+b2c2=0.0025①
(a2+b2+c2)2=a4+b4+c4+2(a2b2+a2c2+b2c2)=0.01②
由①②得出,a4+b4+c4=0.005.
故答案为:0.005.
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