Question

请教如何用php提取图片url地址

Answer 1

1楼的不太符合实际情况,
$str='<p><img border="0" src="upfiles/2009/07/1246430143_1.jpg" alt=""/></p>';
$pattern="/<[img|IMG].*?src=[\'|\"](.*?(?:[\.gif|\.jpg]))[\'|\"].*?[\/]?>/";
preg_match_all($pattern,$str,$match);
print_r($match);

结果:
Array(
[0] => Array ( [0] => <img border="0" src="upfiles/2009/07/1246430143_1.jpg" alt=""/> )
[1] => Array ( [0] => upfiles/2009/07/1246430143_1.jpg )
)

直接获取图片 echo current($match[1]);

Answer 2

<?php
$text ='<a target="_blank" href="http://www.xxx.com/ddd.jpg">';
preg_match_all("/href\=\"(http:[\w\.\/]+\.[\w]+)\"/", $text,$arr);
var_dump($arr[1][0]);
//http://www.xxx.com/ddd.jpg?>