分解因式:x(x-1)(x+1)(x+2)-24=______
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原式=x(x+1)(x-1)(x+2)-24
=x(x2-1)(x+2)瞎基岩-24
=x(x3+2x2-x-2)锋哗-24
=x4+2x3-x2-2x-24
=(x4-2x3)+4x3-x2-2x-24
=x3(x-2)+4x3-8x2+7x2-2x-24
=(x3+4x2)(x-2)+(7x2-14x)+(12x-24)
=(x3+4x2+7x+12)(x-2)
=[(x3+3x2)+(x2+3x)+(4x+12)](x-2)
=(x2+x+4)(x+3)(x-2).
故答案为:(磨御x2+x+4)(x+3)(x-2).
=x(x2-1)(x+2)瞎基岩-24
=x(x3+2x2-x-2)锋哗-24
=x4+2x3-x2-2x-24
=(x4-2x3)+4x3-x2-2x-24
=x3(x-2)+4x3-8x2+7x2-2x-24
=(x3+4x2)(x-2)+(7x2-14x)+(12x-24)
=(x3+4x2+7x+12)(x-2)
=[(x3+3x2)+(x2+3x)+(4x+12)](x-2)
=(x2+x+4)(x+3)(x-2).
故答案为:(磨御x2+x+4)(x+3)(x-2).
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