Question

shell编程:求前10个偶数（2－20）之和 (用while语句写)

速求~~~ 作业中~~~~~

Answer 1

#!/bin/bash
sum=0;
i=2;
while (($i <= 20 )) ; do
sum=$((sum + i));
((i=i+2));
done;
echo $sum;

Answer 2

#!/bin/bash
sum=0;
i=2;
while
(($i
<=
20
))
;
do
sum=$((sum
+
i));
((i=i+2));
done;
echo
$sum;