Question

这题怎么解





Answer 1

var contacts=[

{

"firstName":"akira",

"lastName":"Laine",

"number":"0543236543",

"like":["Pizza","Coding","Brownie Points"]

},

{

"firstName":"Harry",

"lastName":"Potter",

"number":"0994372684",

"like":["Pizza","Coding","Brownie Points"]

}

]

function lookUp(firstName,prop){

for(var i=0;i<contacts.length;i++){

if(contacts[i].firstName==firstName){

var j=0;

for(var key in contacts[i]){

if(key==prop){

console.log(contacts[i][prop]);

break;

}

j++;

}

if(j==4){

console.log("No such property");

}

break;

}

}

if(i==contacts.length){

console.log("No such contact");

}

}

lookUp("Harry","like");

lookUp("Bob","number");

lookUp("Harry","math");

追答

追问

谢谢啦

追答

修改了一下，简化了
function lookUp(firstName,prop){
for(var i=0;i<contacts.length;i++){
if(contacts[i].firstName==firstName){
if(contacts[i][prop]===undefined){
console.log("No such property");
}else{
console.log(contacts[i][prop]);
}
break;
}
}
if(i==contacts.length){
console.log("No such contact");
}
}

追问

谢谢

Answer 2

function lookUp(firstName, prop){
for(var i in contacts){
if(contacts[i].firstName == firstName){
contacts[firstName] = contacts[i];
}
}
if(!contacts[firstName]){
return 'No such contact';
}
if(!contacts[firstName][prop]){
return 'No such property';
}
return contacts[firstName][prop];
}

Answer 3

function lookUpProfile(firstName, prop){
// Only change code below this line
for (var i in contacts)
{if (contacts[i].firstName === firstName && prop in contacts[i])
return contacts[i][prop];}
for ( i in contacts)
{ if (prop in contacts[i] ===false)
return "No such property";
}
for ( i in contacts)
{ if (contacts[i].firstName !== firstName)
return "No such contact";}

// Only change code above this line
}