求数学高手,帮我算下下面这个Y的值,要详细的算法和解释 10
y=39000*(7000/y+6800/y+6600/y+6400/y+6200/y+6000/y)y=39000*(7000*y+6800*y+6600*y+6400...
y=39000*(7000/y+6800/y+6600/y+6400/y+6200/y+6000/y)
y=39000*(7000*y+6800*y+6600*y+6400*y+6200*y+6000*y) 展开
y=39000*(7000*y+6800*y+6600*y+6400*y+6200*y+6000*y) 展开
展开全部
(1) y1+y2=x1^3-3x1^2-sin(πx1)+x2^3-3x2^2-sin(πx2)
=(x1+x2)(x1^2-x1x2+x2^2)-3(x1^2+x2^2)-2sin[(x1+x2)/2π]cos[(x1-x2)/2π]
=2x1^2-2x1x2+2x2^2-3x1^2-3x2^2-2sin(π)cos[(x1-x2)/2π]
=-x1^2-2x1x2-x2^2
=-(x1+x2)^2
=-4
(2) Tn=0+[(2/n)^3+(4/n)^3+…+(2n/n)^3]-3[(2/n)^2+(4/n)^2+…+(2n/n)^2]
+sin(2π/n)+sin(4π/n)+…+sin(2nπ/n)
=8/n^3[1^3+2^3+…+n^3] -12/n^2[1^2+2^2+…+n^2]+sin(2π/n)+sin(4π/n)+…+sin(2nπ/n)
=2(n+1)^2/n-2(n+1)(2n+1)/n+sin(π)sin[(n+1)π/n]csc(π/n)
=2(n+1)/n(n+1-2n-1)
=-2n-2
=(x1+x2)(x1^2-x1x2+x2^2)-3(x1^2+x2^2)-2sin[(x1+x2)/2π]cos[(x1-x2)/2π]
=2x1^2-2x1x2+2x2^2-3x1^2-3x2^2-2sin(π)cos[(x1-x2)/2π]
=-x1^2-2x1x2-x2^2
=-(x1+x2)^2
=-4
(2) Tn=0+[(2/n)^3+(4/n)^3+…+(2n/n)^3]-3[(2/n)^2+(4/n)^2+…+(2n/n)^2]
+sin(2π/n)+sin(4π/n)+…+sin(2nπ/n)
=8/n^3[1^3+2^3+…+n^3] -12/n^2[1^2+2^2+…+n^2]+sin(2π/n)+sin(4π/n)+…+sin(2nπ/n)
=2(n+1)^2/n-2(n+1)(2n+1)/n+sin(π)sin[(n+1)π/n]csc(π/n)
=2(n+1)/n(n+1-2n-1)
=-2n-2
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