求解高数题,求极限,一定有好评?
2个回答
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(14)
x->0
1-cos2x = (1/2)(2x)^2 +o(x^2) = 2x^2 +o(x^2)
1-cos(1-cos2x)
=1-cos[2x^2 +o(x^2)]
= (1/2)(2x^2)^2 +o(x^4)
=2x^4 +o(x^4)
lim(x->0) [ 1-cos(1-cos2x) ]/x^4
=lim(x->0) 2x^4/x^4
=2
(15)
lim(x->0) (cos2x)^(1/x^2)
=lim(x->0) [1- (1/2)(2x)^2 ]^(1/x^2)
=lim(x->0) (1- 2x^2 )^(1/x^2)
=e^(-2)
x->0
1-cos2x = (1/2)(2x)^2 +o(x^2) = 2x^2 +o(x^2)
1-cos(1-cos2x)
=1-cos[2x^2 +o(x^2)]
= (1/2)(2x^2)^2 +o(x^4)
=2x^4 +o(x^4)
lim(x->0) [ 1-cos(1-cos2x) ]/x^4
=lim(x->0) 2x^4/x^4
=2
(15)
lim(x->0) (cos2x)^(1/x^2)
=lim(x->0) [1- (1/2)(2x)^2 ]^(1/x^2)
=lim(x->0) (1- 2x^2 )^(1/x^2)
=e^(-2)
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